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Illusion [34]
3 years ago
8

What is the factored form of x2 - 10x + 24

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0

Answer:

(x-6) (x-4)

Step-by-step explanation:

x^2 - 10x + 24

What 2 numbers multiply to 24 and add to -10

-6*-4 = 24

-6+-4 = -10

(x-6) (x-4)

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Find x so that l || m.
fredd [130]

Answer:

x = 17

Step-by-step explanation:

Line l and m are two parallel lines cut across by the transversal line, therefore, the angle measuring 53° and (8x - 9)° are interior angles on the same side. Interior angles on the same side are supplementary.

Therefore:

53° + (8x - 9)° = 180°

Solve for x

53 + 8x - 9 = 180

Collect like terms

53 - 9 + 8x = 180

44 + 8x = 180

Subtract 44 from both sides

44 + 8x - 44 = 180 - 44

8x = 136

Divide both sides by 8

8x/8 = 136/8

x = 17

3 0
3 years ago
What is 258/300 as a percent
Step2247 [10]
To transform it into percent we want to have 100 into denominator. The easiest way is divide numerator and denominator by 3 (thats because than it doesnt change the value of fraction), so:
\frac{258}{300}= \frac{258:3}{300:3}= \frac{86}{100} = 86% - its the result
4 0
3 years ago
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4n+6b-8 what are the terms
expeople1 [14]
4n, 6b, and -8 are the terms
8 0
2 years ago
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9t-3t+4<br> Please help me ty :)
Ierofanga [76]

Answer: 0.6666666667

Step-by-step explanation: Simplifying

9t + -3t = 4

Combine like terms: 9t + -3t = 6t

6t = 4

Solving

6t = 4

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Divide each side by '6'.

t = 0.6666666667

Simplifying

t = 0.6666666667

8 0
2 years ago
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Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.
daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

5 0
2 years ago
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