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3 years ago

PLEASE HELP ALGEBRA!!

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

Answer:

The very first one is decay and the rest are growth

Step-by-step explanation:

Im SO sorry if i got it wrong

I REALLY hope this helped

Best of luck

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Find the measure of Angle 5. measure of angle 7 = 2x+15 measure of angle 8 = 3x

xenn [34]

Answer:

x=33

Measure of angle 5=81

Measure of angle 6=99

Measure of angle 7=81

Measure of angle 8=99

Step-by-step explanation:

Angles 7 and 8 are supplementary because they share a common vertex while laying on a line.

That is the measurement of angles 7 and 8 add up to be 180.

mAngle7+mAngle8=180

(2x+15) + (3x ) =180

2x+15 + 3x =180

Combine like terms:

5x+15 =180

Subtract 15 on both sides:

5x =180-15

Simplify right hand side:

5x = 165

Divide both sides by 5:

x =165/5

Simplify right hand side:

x =33

The measure of angle 7 is 2x+15=2(33)+15=66+15=81.

The measure of angle 8 is 3x=3(33)=99.

Recall vertical angles are congruent.

5 and 7 are vertical so the measure of angle 5 is 81.

6 and 8 are vertical so the measure of angle 6 is 99.

Measure of angle 5=81

Measure of angle 6=99

Measure of angle 7=81

Measure of angle 8=99

3 0

4 years ago

The graph of y = 4x2 - 4x – 1 is shown.

11Alexandr11 [23.1K]

Answer:

i) The approximate solutions are: $x_{1} \approx -0.207$ , $x_{2} \approx 1.207$ .

ii) The approximate solutions are: $x_{1}\approx -0.5$ , $x_{2} \approx 1.5$ .

Step-by-step explanation:

i) The best approach to estimate graphically the solution of $4\cdot x^{2} - 4\cdot x - 1 = 0$ is graphing the following system of equations:

$y = 4\cdot x^{2}-4\cdot x - 1$ (1)

$y = 0$ (2)

And labeling the points in which both intersects each other. We include the result in the image 'solution-i'. The approximate solutions are: $x_{1} \approx -0.207$ , $x_{2} \approx 1.207$ .

ii) The best approach to estimate graphically the solution of $4\cdot x^{2} - 4\cdot x - 1 = 2$ is graphing the following system of equations:

$y = 4\cdot x^{2}-4\cdot x - 1$ (1)

$y = 2$ (2)

And labeling the points in which both intersects each other. We include the result in the image 'solution-ii'. The approximate solutions are: $x_{1}\approx -0.5$ , $x_{2} \approx 1.5$ .