<u>Step-by-step explanation:</u>
<u>Here </u> ,There are no options given to choose which number is a cube root between 7 & 8 . So below provided answer is way to choose which numbers have cube root between 7 & 8 .
Here , We have to find that Which number has a cube root between 7 and 8 . Let's find out :
We know that ,
![\sqrt[3]{343} = 7\\\sqrt[3]{512} = 8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B343%7D%20%20%3D%207%5C%5C%5Csqrt%5B3%5D%7B512%7D%20%20%3D%208)
So , the number which have cube root between 7 & 8 will surely lie in between of 343 & 512 . Suppose the numbers which which have cube root between 7 & 8 are 
, So these numbers lie between 7 & 8 i.e.
⇒ 
Therefore, all the numbers which lies between 343 and 512 or , have a cube root between 7 & 8 .
the answer is d or the last one
To find the lower quartile take the number of terms=n=12
to find the lower quartile take the equation (n+1)/4= 3.25
this means that the lower quartile will be at the 3.25th position int he sequence when all the terms are ordered from smallest to largest. so when ordered: 12 19 19 19.5 20 28 28 28.5 34 36 45 45
so the lower quartile is between 19 and 19.5 exactly 19.125
Answer:
y=mx+b
Step-by-step explanation:
b is wherever the line intersects the y axis.
m is the slope, rise/run. hope this helps! please mark brainliest!
\left[x \right] = \left[ 5\right][x]=[5]2(x+1)/−2 = 8−2 _________
_________ Simplifying
\left[x \right] = \left[ 2\right][x]=[2] = x + 1 + -4
x = -5
