The minimum value for 2x is 0
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>
<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>
<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>
<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>
<span>sin 2x = 22 (sin 34°)/30 </span>
<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>
<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>
<span>0 < x < 12.1°</span>
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given

The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.

Slope intercept form is:

Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation

Putting the values of b and m

Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
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Answer:
-30 i guess
Step-by-step explanation:
Answer: B Or A
Step-by-step explanation: