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Akimi4 [234]
3 years ago
6

What is the explicit formula for the sequence? 6, 5, 4, 3, 2, . . .

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0
I think that the right answer for this question is  6
You might be interested in
Randy rented a rectangular storage shed with the volume of 357 ft does it sheds height is 8 and 1/2 ft and the width of is 6 ft
ollegr [7]

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

357 = L * 6 ft * 17/2 feets

357 feets³ = L * 51 feets²

L = 357 feets³ / 51 feets²

Length, L = 7 feets

7 0
3 years ago
A stack of identical 8-centimeter-by-10-centimeter rectangular playing cards is sitting on a table. The stack is 1 centimeter hi
snow_lady [41]

Answer: A, B, C.

If the stack of cards are shifted so it is not straight, it still has everything the same.

7 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
6=1-2n+5 how do I solve this?
Ivanshal [37]
6=1-2n+5\\ \\2n=1+5-6\\ \\ 2n=0\ \ /:2\\ \\ n=0
5 0
3 years ago
Read 2 more answers
A bag contains 22 red marbles, 8 white marbles, and 3 gray marble. You randomly pick out a marble, record its color, and put it
frez [133]

Total marbles : 33

W + G marbles : 11

Probability of picking either a W or G : 11/33

Number of W or G marbles = 11/33 × 45 = 15

4 0
3 years ago
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