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Sever21 [200]
3 years ago
13

Find the volume of the solid obtained by rotating the region under the curve y = x3 about the line y = -1 over the interval [0,1

].
a. 33pi/14
b. 9pi/19
c. 5pi/14
d. 5pi/19
Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

I beileve its b

Step-by-step explanation:

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The side length of a cube is √7 cm.
Genrish500 [490]
<span>The answer is The total area of the top and bottom squares. s = √7 cm is irrational value and we need rational value. Let's check all choices: A. The volume. V = (s)^3. If s = √7, V = (√7)^3 = 7√7 - irrational value. B. The perimeter of the front square. P = 4 * s = 4 * √7 = 4√7 - irrational value. C. The diagonal of the back square. d = s√2 = √7 * √2 = √(7*2) = √14 - irrational value. D. The total area of the top and bottom squares. A = 2 * s^2 = 2 * (√7)^2 = 2 * 7 = 14 - rational value.</span>
6 0
3 years ago
ASAP!!! GIVING BRAINLIEST!!
igomit [66]

Answer:

The answer will be y-4=-2(x+1)

5 0
3 years ago
Literally answer any of the questions above and it’ll be the biggest help
Tcecarenko [31]

The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.

We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.

a) The cosine values repeat every 2π, so the general form of the smallest angle will be

... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ

b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is

... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ

c) Using these expressions with k=0, 1, 2, we get

... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}

3 0
4 years ago
What is the 4th term of the expanded binomial (2x – 3y)^6
san4es73 [151]

Answer:

The 4th term of the expanded binomial is -4320x^3y^3

Step-by-step explanation:

Considering:

$ (x+y)^n = \sum_{k=0}^{n} \binom{n}{k}  x^{n-k}y^k$

$ (2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k}  (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of k

$ (2x-3y)^6 = \binom{6}{0}  (2x)^{6-0}(-3y)^0     +       \binom{6}{1}  (2x)^{6-1}(-3y)^1     +      \binom{6}{2}  (2x)^{6-2}(-3y)^2   +   \\ $

$\binom{6}{3}  (2x)^{6-3}(-3y)^3    +    \binom{6}{4}  (2x)^{6-4}(-3y)^4    +  \binom{6}{5}  (2x)^{6-5}(-3y)^5    +    \binom{6}{6}  (2x)^{6-6}(-3y)^6            $

I will not write every product, but just solve following the steps:

For k=0

$\binom{6}{0}  (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)}   (2x)^{6-0}(-3y)^0$

$ \frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

64x^6

(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6

8 0
3 years ago
Which of the following binary numbers is equivalent to decimal 9? A. 101 B. 1001 C. 1010 D. 10000
zimovet [89]

Answer:

the answer is b.1001 as the equvalent number to the decimal 9

5 0
3 years ago
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