What we know:
12 hour period from 8pm to 8am
temperature dropped from 8°F to 16°F from 8pm to 8am
We need to find temperature at 4 am.
We can start by setting up points:
8pm is are starting point with 8°F, we can express it as (0,8), 0 represents initial time from 0 to 12 hour span.
8am is the ending point with 16°F, we can express it as (12,16), 12 represents the end time of 0 to 12 hours span.
We will use these points to find slope.
slope=m=(16-8)/(12-0)=8/12=2/3
Now, we can set up an expression to find any temperature at a specific time. Aslo, x represents the hours not the the specific time of 4am. We will use 8 since 4am is the 8th hour of the 12 hour span. Using slope of 2/3 and the y intercept of (0,8) since we were already at 8°F at the initial time of 0 we have the function:
f(x)=2/3x+8
f(8)=2/3(8)+8= 40/3≈13.3°
Distribute the “-3” to both n&-3 —> -3n+9 then your left with -5 and subtract 9-5
-3n+4
Hope this helps:)
Answer:
f(-3) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = -1x - 4
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(-3) = -1(-3) - 4
- Multiply: f(-3) = 3 - 4
- Subtract: f(-3) = -1
Answer:
Result: $26.46
Steps:
$24.50 (increase) + 8% = $26.46
24.50 x (1 + 8%) = 24.50 x (1 + 0.08) = 26.46
I'm truly sorry if my math is incorrect.
Bye, have a great day/night :)