70.33 L is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm.
<h3>What is volume?</h3>
Volume is the percentage of a liquid, solid, or gas's three-dimensional space that it occupies.
Liters, cubic metres, gallons, millilitres, teaspoons, and ounces are some of the more popular units used to express volume, though there are many others.
We will use ideal gas law to find the volume
PV = nRT
Can also be written as
V = (nRT)/P
Where,
P = pressure
V = volume
n = amount of substance
R = ideal gas constant
T = temperature
Here, we have given
P = 3.5 atm
V = to find
n = 10 moles
R = 0.08206 L⋅atm/K⋅mol
T = 300k
Lets substitute the values
V = (10 × 0.08206 × 300)/3.5
V = 70.33 L
Learn more about volume
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Answer : The partial pressure of
is, 88.84 atm
Solution :
The given equilibrium reaction is,
![2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)](https://tex.z-dn.net/?f=2SO_2%28g%29%2BO_2%28g%29%5Crightleftharpoons%202SO_3%28g%29)
= 36.9 atm
= 16.8 atm
The expression of
will be,
![K_p=\frac{(p_{SO_3})^2}{(p_{O_2})(p_{SO_2})^2}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%28p_%7BSO_3%7D%29%5E2%7D%7B%28p_%7BO_2%7D%29%28p_%7BSO_2%7D%29%5E2%7D)
Now put all the values in this expression, we get
![0.345=\frac{(p_{SO_3})^2}{(16.8)\times (36.9)^2}](https://tex.z-dn.net/?f=0.345%3D%5Cfrac%7B%28p_%7BSO_3%7D%29%5E2%7D%7B%2816.8%29%5Ctimes%20%2836.9%29%5E2%7D)
![(p_{SO_3})=88.84atm](https://tex.z-dn.net/?f=%28p_%7BSO_3%7D%29%3D88.84atm)
Therefore, the partial pressure of
is, 88.84 atm
You would need 9 atoms of nitrogen,
So the correct answer would have to be, B. Hope this helps
Answer:
Citrate synthase, acetyl-CoA
Explanation:
Beta oxidation is the process by which fatty acid molecules are broken down in prokaryotes' cytosol and in eukaryotes' Mitochondria to produce acetyl-CoA. The overall reaction in Beta oxidation is given below;
Cn-acyl-CoA + FAD + NAD^+ + H2O+ CoA ------------->Cn-2-acyl-CoA + FADH2 + NADH + H^+ + acetylCoA.
Beta-oxidation occurs by cleaving two carbons every cycle to form acetyl-CoA. It involves four process.
(1). Dehydrogenation of long chain fatty acids to create trans C2 and C3. This process is catalyzed by acyl CoA dehydrogenase.
(2). The hydration of Trans-delta2-enoyl CoA to produce L-3-hydroxyacyl CoA. This process is catalyzed by enoyl-CoA hydratase.
(3). The re-hydrogenation of L-3-hydroxyacyl CoA to produce 3-ketoacyl CoA in the presence of 3-hydroxyacyl CoA dehydrogenase.
(4). Thyolysis. In this process, thiolase enzyme catalyzes the reaction. A new molecule of coenzyme A breaks the bond by nucleophilic attack on C3.
The question is incomplete, the complete question is:
A chemist prepares a solution of vanadium (III) chloride (VCl3) by measuring out 0.40g of VCl3 into a 50.mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Cl− anions in the chemist's solution. Be sure your answer is rounded to the correct number of significant digits.
Answer:
0.153M of anions
Explanation:
First we calculate the concentration of the solution. From m/M= CV
m=given mass, M= molar mass, C =concentration of solution, V= volume of solution
Molar mass of compound= 51 + 3(35.5)= 157.5gmol-1
0.4g/157.5gmol-1= C×50/1000
C= 2.54×10-3/0.05= 0.051M
But 1 mole of VCl3 contains 3 moles of anions
Therefore, 0.051M will contain 3×0.051M of anions= 0.153M of anions