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Masteriza [31]
3 years ago
7

Which quantity or quantities must always be the same on both sides of a chemical equation? check all that apply. check all that

apply. the number of atoms of each kind the number of moles of each kind of molecule the sum of the masses of all substances involved the number of molecules of each kind?
Chemistry
2 answers:
Darya [45]3 years ago
6 0

Answer:

- The number of atoms of each kind.

- The sum of the masses of all substances involved.

Explanation:

Hello,

Chemical reactions are chemical processes wherein a series of reactants undergo a change in their composition due to a bond breaking caused by energetic means. In this manner, such change is constricted by two conditions which must be assured after the chemical reactions, they are:

- The number of atoms of each kind.

- The sum of the masses of all substances involved.

They are based on the law of conservation of mass which states that the mass can not be neither created nor destroyed, thus, the number of atoms of each kind and the sum of the masses must remain equal before and after the chemical reaction. For instance, consider the reaction:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Whereas the stoichiometric coefficients guarantees the first condition and the complete consumption-production the second one.

Best regards.

blagie [28]3 years ago
5 0

what are the answer choices?
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Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and
sammy [17]

Answer:

The answer is explained below:

Explanation:

Given the chemical equation:

                   N2H4(g)+H2(g)→2NH3(g)

The standard enthalpy of formation is given by the following formula:

            ΔH^0 rxn = ∑ B reactants - ∑ product

       -187.78 kJ/mol = [( 1x B N-N) + (1 x B N-H ) + (1 x b H-H)] - [ 6 x B N-H]

       -187.78 kJ/mol = [( 1x B N-N)  +(4 x 391 kJ/mol) + (1 x 436  kJ/mol)] - [ 6x 391  kJ/mol ]

        -187.78 kJ/mol =  B N-N  + (1564 + 436 - 2346) kJ/mol

                                       B   = 158.22 kJ/mol

So, in this case the enthalpy of N-N bond is 158 kJ/mol

6 0
3 years ago
The positively charged particles in an atoms nucleus is the A electron. B neutron. C proton. D isotope.
Mama L [17]

Answer:

Proton

Explanation:

3 0
3 years ago
Which part of the periodic table contains elements with the greatest metallic properties?
KiRa [710]
The bottom of group 1. Francium (or Fr) is the element with the greatest metallic properties.

Francium is not a naturally-occurring element, however. It is man-made. There is an isotope of francium that exists naturally, but it's half life is so short that it decays almost instantly into a different element.

The naturally-occurring element with the highest metallic properties is cesium (or Cs), located right above francium.

Metallic characteristics decrease as you move from left to right on the periodic table.
7 0
3 years ago
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm  ; Final Volume = 1.8 L ; Final pressure = 0.73 atm  

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T_2 ),

P_1V_1 / T_1 = P_2V_2 / T_2,

T_2 = P_2V_2T_1 / P_1V_1,

T_2 = 0.73 atm * 1.8 L * 298.15 K / 1 atm * 1.2 L = ( 0.73 * 1.8 * 298.15 / 1 * 1.2 ) K = 326.47425 K,

T_2 = 326.47425 K = 53.32425 C

7 0
3 years ago
If a helium filled ballon has a volume of 3.4l at 25°c and 1.18atm., what is its volume at STP?​
vladimir2022 [97]

Answer:

3.711 L

Explanation:

The formula you need to use is the following:

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\

3.4L / 298 K = V2 / 273 K

V2 = 3.711 L

5 0
3 years ago
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