For g(x)=x^2-x find g(x) when x=-2
1 answer:
Answer:
Step-by-step explanation:
Begin with substuting the x variable with -2, we do this because the question has listed the value of x already.
Using the value of x, -2 we determine g(x).
g(x) = -2^2 + 2
Above is what the equation would look as, after you input the value of -2.
Using pemdas, (parantheses, exponents, multiplication, division, addition, subtraction) solve the equation.
-2^2 = 4
Think of it as -2 * -2, which is why -2^2 is 4.
Add 4 +2.
4 + 2 = 6.
Therefore, the value of g(x) = 6
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Answer:
35 <5m
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7 < m
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a + 6 9
a + 6 - 6 9 -6
a 3
a = 3,4,5,6,7,......
8-g > 5
8 -g +g > 5 +g
8 > 5 +g
8 -5 > 5 -5 +g
3 > g
g =4,5,6,7,8.......
Step-by-step explanation:
When the sign is ≤ or ≥ ("less/greater than <u>or equal to</u>"), the dot if filled in.
When the sign is < or >, the dot is not filled in/open circle.
15 > m
[15 is greater than m, or m is less than 15]
Since m is less than 15, the arrow is going to the left (the numbers to the left are less than 15)
