Answer: 90.82%
Step-by-step explanation:
Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .
Mean : ![\mu=16.12\text{ OZ}](https://tex.z-dn.net/?f=%5Cmu%3D16.12%5Ctext%7B%20OZ%7D)
Standard deviation: ![\sigma=0.09\text{ OZ}](https://tex.z-dn.net/?f=%5Csigma%3D0.09%5Ctext%7B%20OZ%7D)
Let X be the random variable that represents the amount of soda in bottles.
Formula for z-score : ![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Z-score for 16 oz: ![z=\dfrac{16-16.12}{0.09}=-1.33](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B16-16.12%7D%7B0.09%7D%3D-1.33)
Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_
![P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%](https://tex.z-dn.net/?f=P%28x%3E60%29%3DP%28z%3E-1.33%29%3D1-P%28x%5Cleq-1.33%29%3D1-0.0917591%3D0.9082409%5Capprox0.9082%5Capprox90.82%5C%25)
Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .
Answer:
Yes, because 42 squared + 56 squared = 70 squared.
Step-by-step explanation:
Answer:
Yes that is 7.
Step-by-step explanation:
It would be 7x7 + 2x2 = 53
Answer:
f(x^2)=3x^2+5
Step-by-step explanation:
math