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denis-greek [22]
3 years ago
9

S m a r t p e o p l e o n l y please help me!

Mathematics
2 answers:
harina [27]3 years ago
4 0

Answer:

answer is 11: 37 am

I am sure ;-))

frutty [35]3 years ago
3 0
The answer is 11:37 am
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Circular garden in the middle of a square yard. The radius of the circle is 4x. The side length of the yard is 20x. What is the
dusya [7]
-- The area of the entire yard, before the garden was planted, was

             (side)²  =  (20x)²  =  400 x² .

-- The area of the circle where garden was put in is

             pi R²  =  (pi) · (4x)²  =  16 pi x² .

--  The remaining area of the yard ... the part not covered by
the circular garden ... is

           (400x²) - (16pi x²)  =  x² (400 - 16pi)

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4 years ago
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3 years ago
If x+y=5,then what is the value of x3+y3+15xy​
a_sh-v [17]

Answer:

125

Step-by-step explanation:

x + y = 5

We need to have x^3 and y^3 in the expression, so cube both sides.

(x + y)^3 = 5^3

Expand the left side.

(x + y)(x + y)^2 = 125

(x + y)(x^2 + 2xy + y^2) = 125

x^3 + 2x^2y + xy^2 + x^2y + 2xy^2 + y^3 = 125

x^3 + 3x^2y + 3xy^2 + y^3 = 125

Now we need to separate x^3 + y^3.

x^3 + y^3 + 3x^2y + 3xy^2 = 125

We need to turn 3x^2y + 3xy^2 into 15xy.

Factor the GCF, 3xy, out of 3x^2y + 3xy^2.

x^3 + y^3 + 3xy(x + y) = 125

We know that x + y = 5, so substitute x + y with 5.

x^3 + y^3 + 3xy(5) = 125

x^3 + y^3 + 15xy = 125

Answer: 125

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