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ella [17]
3 years ago
6

A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer:

y = 3x + 12

Step-by-step explanation:

Lines parallel to each other will have the same slope but different y-intercepts. This means that the equation of this parallel line has a slope of 3.

y = 3x + b

Now we need to find the y-intercept by plugging in the point (-2, 6) into the equation. (Replace x with -2 and y with 6.) Then we solve it.

y = 3x + b

6 = 3(-2) + b

6 = -6 + b

+6 +6

12 = b

The y- intercept is 12. So the equation of the parallel line is y = 3x + 12

sveta [45]3 years ago
4 0

Answer:

y = 3x + 12

Step-by-step explanation:

Slope of y = 3x + 5 is 3

Line parallel will have same slope 3

Line intersects point at (-2, 6)

Replace into y = mx + b to find

6 = 3(-2) + b

6 = -6 + b

12 = b

Equation of line:

y = 3x + 12

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  StartFraction 50 miles Over 1 hour EndFraction = StartFraction 200 miles Over question mark hours EndFraction

Step-by-step explanation:

For constant speed, miles and hours are proportional. One possible equation is ...

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The face of the triangular concrete panel shown has an area of 22 square meters, and its base is 3 meters longer than twice its
Elodia [21]

Answer:

The length of the base is 11 meters.

Step-by-step explanation:

The diagram of the triangle is not shown; However, the given details are enough to solve this question.

Given

<em>Shape: Triangle</em>

<em>Represent the height with h and the base with b</em>

b = 3 + 2h

Area = 22

Required

Find the length of the base

The area of a triangle is calculated as thus;

Area = \frac{1}{2} * b * h

Substitute 22 for Area and 3 + 2h for b

The formula becomes

22 = \frac{1}{2} * (3 + 2h) * h

Multiply both sides by 2

2 * 22 = 2 * \frac{1}{2} * (3 + 2h) * h

44 = (3 + 2h) * h

Open the bracket

44 = 3 * h + 2h * h

44 = 3h + 2h^2

Subtract 44 from both sides

44 - 44 = 3h + 2h^2 - 44

0 = 3h + 2h^2 - 44

Rearrange

0 = 2h^2 +3h - 44

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At this point, we have a quadratic equation; which is solved as follows:

2h^2 +3h - 44 = 0

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(h - 4)(2h + 11) = 0

Split the above

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Solve the above linear equations separately

h - 4 = 0

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h - 4 + 4 = 0 + 4

h = 0 + 4

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Subtract 11 from both sides

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2h  = 0 - 11

2h = -11

Divide both sides by 2

\frac{2h}{2} = -\frac{11}{2}

h = -\frac{11}{2}<em> ------ Second value of h</em>

Since height can be negative, we'll discard h = -\frac{11}{2}

Hence, the usable value of height is h = 4

Recall that b = 3 + 2h

Substitute 4 for h

b = 3 + 2(4)

b = 3 + 8

b = 11

Hence, the length of the base is 11 meters

3 0
4 years ago
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