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3 years ago

A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?

Mathematics

2 answers:

Alenkasestr [34]3 years ago

6 0

Answer:

y = 3x + 12

Step-by-step explanation:

Lines parallel to each other will have the same slope but different y-intercepts. This means that the equation of this parallel line has a slope of 3.

y = 3x + b

Now we need to find the y-intercept by plugging in the point (-2, 6) into the equation. (Replace x with -2 and y with 6.) Then we solve it.

y = 3x + b

6 = 3(-2) + b

6 = -6 + b

+6 +6

12 = b

The y- intercept is 12. So the equation of the parallel line is y = 3x + 12

sveta [45]3 years ago

4 0

Answer:

y = 3x + 12

Step-by-step explanation:

Slope of y = 3x + 5 is 3

Line parallel will have same slope 3

Line intersects point at (-2, 6)

Replace into y = mx + b to find

6 = 3(-2) + b

6 = -6 + b

12 = b

Equation of line:

y = 3x + 12

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