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3 years ago

How could you determine the coordinates of the verticals of a translated image without using a graph

Mathematics

1 answer:

Tju [1.3M]3 years ago

3 0

Answer:

haha82829sjsjsm81kqqma s.sksjsjwnq9292929snakw999

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Which point is not on the graph of the equation y=10+x

RSB [31]

Answer:

C. (8, 2)

Step-by-step explanation:

To find which point is not on the graph, find which set of coordinates makes the equation incorrect.

When plugged into the equation, the point (8, 2) makes it incorrect:

y = 10 + x

2 = 10 + 8

2 = 18

2 $\neq$ 18

The equation is incorrect because 2 is not equal to 18.

So, the point that is not on the graph is C. (8, 2)

6 0

2 years ago

An Item priced at $776 has a sales tax of $48.50. Find the sales tax rate expressed as a percent.

amid [387]

48.50/776 = .0625 or 6.25%

6 0

2 years ago

Read 2 more answers

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0

2 years ago

{29, 29, 29, 28, 28, 27}

gregori [183]

I think the answer is B Mean or median because there is no outlier.

3 0

2 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago