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masha68 [24]
3 years ago
11

Ill give brainliest Exterior Angle Theorem CLASSWORK

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer & Step-by-step explanation:

7). C = 44

8). S = 40

9). S = 40

10). T = 118

You can write in the comments if you want an explanation.

Hope this help ;)

bija089 [108]3 years ago
4 0

Answer:

Let the required angle be x

7). x + 22 = 66 \\  \boxed{x = 44°}

<h3>44° is the right answer.</h3>

8). x + 60 = 110 \\  \boxed{x = 50°}

<h3>50° is the right answer.</h3>

9). x  + 75 = 105 \\ \boxed{ x = 30°}

<h3>30° is the right answer.</h3>

10). x = 31 + 87 \\\boxed{ x = 118°}

<h3>118° is the right answer.</h3>
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At what annual rate of return compounded monthly would your investment grow from $7500 to $10000 in 20 years
harina [27]

Answer:

Using the attached formula:

exp = log (total/principal) / n * years

exp = log (10,000 / 7,500) / 12 * 20

exp = log (1.3333333333) / 240

exp = 0.1249387366 / 240

exp = 0.000520578069166667

rate = (10^exp -1) * n

rate = (10^0.000520578069166667  -1) * n

rate = 1.00119939400018  -1 * n

rate = .00119939400018 * 12

rate = 0.014392728

OR rate = 1.4392728 % Compounded Monthly

OR rate = 1.448805264762% Compounded Annually


Step-by-step explanation:


7 0
3 years ago
Three students simplified the expression 2x- 3(y-2x) +-5times -2y.
Tom [10]
Carl is right because simplifying it gets us: 2x-3y+6x+10y=8x+7y
7 0
3 years ago
.
Nonamiya [84]

The only point outside of the line is (2, 0)

In order to find if a point is outside, inside or on the line, you simply have to put the number into the equation. If the result is both sides are equal, then it is on the line. If the left side is bigger than the right side, then it is outside of the line. If the right side is bigger than the left, then it is inside of the line. So lets plug in and see where (2, 0) falls.

(x - 2)^2 + (y + 3)^2 = 4

(2 - 2)^2 + (0 + 3)^2 = 4

0^2 + 3^2 = 4

0 + 9 = 4

9 = 4

Since the left side is bigger than the right, we know it is outside of the line.

3 0
3 years ago
A 10-foot ladder leans against a wall with its foot braced 3 feet from wall's base. How far up the wall does the ladder reach?
dlinn [17]
Pythagorean theorem
for a right triangle with legs legnth a and b and hytponuse c
a^2+b^2=c^2

the legnht of th eladder is the hypotnuse
the 3 feet is bottom leg
height is other leg

10=c
3=a
b=?
3^2+b^2=10^2
9+b^2=100
minus 9 both sides
b^2=91
sqrt both sides
b=√91
aprox
b=9.53939


answer is √91 feet or aprox 9.53939
8 0
3 years ago
4. Using the formula below, solve when S=1.50 <br> A = 6s2
Lesechka [4]

the answer would be 13.5

1.5^2=2.25

6x2.25=13.5

8 0
3 years ago
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