Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:
The value of
is
.
Step-by-step explanation:
We know that the position function is given by

Velocity is defined as the rate of change of position. Therefore,

So, the velocity function is

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).
So, the value of
is
.
I did this equation and it’s A
Answer: 64
Step-by-step explanation:
y=8
plug in 8 for y
2(8)=64