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3 years ago

How to do this cause I'm very lost

Mathematics

1 answer:

Jlenok [28]3 years ago

5 0

You put the 0 if it is close to 0, the 1/2 if it is closer to half, 1 if it is equal or closer to one, and the >1 if it is over one

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If log10(x^{2}y^{3})=7 and log10 (x/y)=1 , then x=__ and y= __

yuradex [85]

Answer:

$x=100$

$y=10$

Step-by-step explanation:

we are given

$log_1_0(\frac{x}{y})=1$

Firstly, we will get rid of log

so, we will take exponent over 10 on both sides

$10^{log_1_0(\frac{x}{y})}=10^{1}$

now, we can simplify it

$\frac{x}{y}=10$

now, we can solve for x

$x=10y$

we are given

$log_1_0(x^2y^3)=7$

Firstly, we will get rid of log

so, we will take exponent of 10 on both sides

$10^{log_1_0(x^2y^3)}=10^7$

$x^2y^3=10^7$

now, we can plug back x from first equation

$(10y)^2y^3=10^7$

now, we can solve for y

$100y^5=10000000$

$\frac{100y^5}{100}=\frac{10000000}{100}$

$y^5=100000$

now, we can take radical 5

$y=\sqrt[5]{100000}$

$y=10$

now, we can find x

$x=10\times 10$

$x=100$

So, solution is

$x=100$

$y=10$

4 0

4 years ago

PLEASE HELP I SUCK AT MATH I APPRECIATE IT❤️❤️

SSSSS [86.1K]

Answer:

1 term 3x²

two term x+8, 3x³ +5x²

3 term 2x²+x-3

Step-by-step explanation:

4 0

3 years ago

If x = -2, then x 2-7x+10 equals <br> a. 0 <br> b.20 <br> c.28

sveta [45]

ANSWER

C. 28

EXPLANATION

The given expression is

${x}^{2} - 7x + 10$

We want to evaluate this function at x=-2.

We just have to substitute x=-2 into the given expression.

In other words, we have to replace x with -2 wherever we see x in the expression

${( - 2)}^{2} - 7( - 2) + 10$

We evaluate the exponent to get

$4 - 7( - 2) + 10$

We multiply next to get:

$4 + 14+ 10$

We now add to obtain:

$28$

The correct answer is C

6 0

3 years ago

Factor completly . x^5 -x^4 - x^3

diamong [38]

Answer

Step-by-step explanation:

7 0

3 years ago

HELLLLLLLLLPPPPPPP The difference of two numbers is 8 and their quotient is 2

Dmitriy789 [7]

Answer:

x-y =8

x/y=3

=> 3y-y=8

=> 2y = 8

=> y = 4

=> x = 4+8 =12

3 0

3 years ago