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3 years ago

Using the following triangle, what is the sine of angle A?

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

Answer: sinA = a/c

Explanation: Since A is the angle, b is the adjacent side and c is the hypotenuse since it is across the 90 degree point. Side a is the opposite side, sine is opposite/hypotenuse.

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Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,

Arisa [49]

ANSWER

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

EXPLANATION

The given function is

$y = {x}^{2} \cos(x)$

We take natural log of both sides;

$ln(y) = ln({x}^{2} \cos(x) )$

Recall and use the product rule of logarithms.

$ln(AB) = ln(A ) + ln(B)$

This implies that:

$ln(y) = ln({x}^{2} ) + ln( \cos(x) )$

$ln(y) = 2 ln({x} ) + ln( \cos(x) )$

We now differentiate implicitly to obtain;

$\frac{ {y}^{'} }{y} = \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) }$

Multiply through by y,

${y}^{'} = y( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) })$

Substitute y=x²cosx to obtain;

${y}^{'} = {x}^{2} \cos(x) ( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) } )$

Expand:

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

7 0

3 years ago

A class of 30 swim team members took a lifesaving test. Eighteen of the members had an average score of 92 points. The remaining

inysia [295]

Answer:

88.8%

Step-by-step explanation:

1.) 30-18= 12 which is the number of member that had an average of 84

2.)Then multiply 12 times 84 = 1008

3.) You multiply 18 by 92 which equals 1656

4.)Add 1008 and 1656 together and get 2664.

5.)Divide 2664 / 30 and you get the average of 88.8

Hope this helps :)

plz brainly & like

8 0

3 years ago

Read 2 more answers

Can y’all follow me on ig and Twitter at Baggboynick ?

Gemiola [76]

Answer:

sure eeeeeeeeeee

Step-by-step explanation:

let me download twitter lol

7 0

2 years ago

Read 2 more answers

What is the slope of a line containing (4,6) and (0,8)?

AlladinOne [14]

Answer:

$m=\frac{-1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (4, 6)

Point (0, 8)

Step 2: Find slope m

Substitute: $m=\frac{8-6}{0-4}$
Subtract: $m=\frac{2}{-4}$
Simplify: $m=\frac{-1}{2}$

3 0

2 years ago

Read 2 more answers

I don't know to find the answer to 8. Can someone explain to me?

lapo4ka [179]

Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.

7 0

2 years ago