therefore, sin(x) = cos(90° - x).
The triangles are shown to be similar, therefore
The answer is 9 units
Answer:
m∠C = 60°
Step-by-step explanation:
we know that sum of angles of a traingle is 18 degrees.
given
m∠A = 60°+α,
m∠B = 60°−α
we have to find m∠C
m∠A + m∠B + m∠C = 180
60°+α + 60° - α +m∠C = 180
+α and -α gets cancelled
120°+m∠C = 180
=> m∠C = 180° - 120° = 60°
Thus, measure of angle c is 60°.
If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.
Given Part A:
the volume of the cube = 64 cubic feet
therefore, ∛64 = 4 feet
hence one edge measures 4 feet.
Now for Part B:
the area of the square is 12 square feet.
hence, √12 = 3.36 feet.
we can observe that 3.46<4
which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.
Hence the painting will fit a side of crate.
Learn more about Area and Perimeter here:
brainly.com/question/24571594
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Your question was incomplete. Please find the missing content here.
While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.
Answer:
The sample 2 has a lowest value of SE corresponding to the least sample variability.
Step-by-step explanation:
As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows
The data is as attached with the solution. From this data
Sample 1 has a mean of 34 and a SE of 5
Sample 2 has a mean of 30 and a SE of 2
Sample 3 has a mean of 26 and a SE of 3
Sample 4 has a mean of 38 and a SE of 5
As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .
So the sample 2 has a lowest value of SE corresponding to the least sample variability.
