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Lyrx [107]
3 years ago
11

What is equivalent to 6/8?

Mathematics
1 answer:
patriot [66]3 years ago
4 0
3/4
75%
0.75
75/100
theres a lot
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In the following number, which digit is in the hundredths place?<br><br> 745312.269784
Greeley [361]

Answer:

The second number after the decimal point- the 6

6 0
3 years ago
Read 2 more answers
Need help due tomorrow plz help!!
Sonbull [250]
1.) B

because it says the person buys a ski for 350. He puts down $110 which means to subtract. Now he got a discount which also means to subtract. Then it told that he gave 1/2 them money to his mother. So that too means to subtract. 

2.) 2+5n

because it says 2 plus 5 times a number. So 2+5×n 
6 0
3 years ago
Determine which of the following equations, when graphed, intersect at the point (4, 0). Select all that apply. x - y = 4 -x - y
Elza [17]

Answer: only (x-y=4) and (x+y=4).


Step-by-step explanation:

Notice target point has y=0, so all terms with y are zero. Then all 6 equations reduce to m x = k, for various m and k. So calculate 4×m and compare to k six times.


x - y = 4 4=4 yes

-x - y = 4 -4=4 no

2x - y = 7 8=7 no

x + y = 4 4=4 yes

2x + y = 7 8=7 no

2x + y = -7 8=-7 no.

6 0
3 years ago
Read 2 more answers
What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
3 years ago
I need an answer to this problem​
makkiz [27]
The answer is c
This is because only the y-int changes
6 0
3 years ago
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