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drek231 [11]
2 years ago
10

HELP PLZ DUE RN BRAINIEST TO WHOEVER RIGHT

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
5 0

Answer: x=0.25

Step-by-step explanation: 1−8x=−16x2

Simplify both sides of the equation.

−8x+1=−16x2

Subtract -16x^2 from both sides.

−8x+1−−16x2=−16x2−−16x2

16x2−8x+1=0

16x2+−8x+1=0

Use quadratic formula with a=16, b=-8, c=1.

x=

−b±√b2−4ac

2a

x=

−(−8)±√(−8)2−4(16)(1)

2(16)

x=

8±√0

32

x=0.25

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Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in
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<h2>\large\bold{\underline{\underline{Question:-}}}</h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

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\underline{ \underline{ \sf{Let's \:  find  \: the  \: ratio  \: of \:  their  \: volumes:}}}

{ \implies{ \sf  {V _{1}  :  V_{2}}}}

{ \implies{ \sf{ \frac{1}{3} \pi \:  { r_{1}}^{2}  h_{1} :  \frac{1}{3}  \pi \:  { r_{2} }^{2}  h_{2}}}}

{ \implies{ \sf{ {r_{1}}^{2}  h_{1} :  { r_{2}}^{2} h_{2}}}}

{ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} }  :  \frac{ h_{2} }{ h_{1} } }}} \\

{ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} }  :  \frac{3}{1} }}} \\

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{ \therefore{ \sf{ \green{Ratio  \: of  \: their \:  volumes = 3 : 1}}}}

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Step-by-step explanation:

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Read 2 more answers
Evaluating Expressions<br>x-7<br><br> for x=-8 <br><br>for x=-11<br><br>for x= 16
kow [346]
You just substitute in what x equals. ex. x=16, x-7 : 16-7=9.

x-7

1. x= -8; -8-7= -15
2. x= -11; -11-7= -18
3. x=16; 16-7= 9
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3 years ago
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