The answer is D as it can be rewritten as -((y^2)/5)-(8/5)=x. Solving for the x-intercepts you get -((y^2)/5)-(8/5) = 0 as you want to find the y values when x is zero. Solving for y you get: (y^2)/5)+(8/5) = 0 => (y^2)/5)=-(8/5) => y^2=-8 => y = plus or minus sqrt(-8). The first problem is that you have 2 x intercepts which already makes it not a function and second sqrt(-8) is an imaginary number making the solution not a real number.
Answer: negative, positive
Step-by-step explanation:
Answer:
Find the equation of the line that is parallel to y=4x+1 and contains the point (1,1)
Substitute 1 for x and 1 for y in y=4x+1.
1=4(1)+1
The given point does not make the equation true.
Invalid Point
Step-by-step explanation:
LCM answers:
1. 28
2. 60
3. 84
