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3 years ago

Minutes in x hours. Just need the answer please

Mathematics

2 answers:

Gnesinka [82]3 years ago

8 0

Answer:

There is no question

Step-by-step explanation:

kherson [118]3 years ago

3 0

Answer:

There are 60 minutes in a hour. One minute is equal to 6 × 10^1 to unit of time second. Therefore 1 minute = 60 seconds. 1 hour = (3600 seconds / 60 seconds) minutes.

Step-by-step explanation:

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Joshua had $415.29. He got $175 for his birthday and spent $59.99 on a video game. How much money will he be able to deposit int

babunello [35]

Answer:

530.30

Step-by-step explanation:

The equation would be m=415.29 + 175 - 59.99.

When you solve the equation, the answer is 530.3.

4 0

3 years ago

A^3b^-2c^-1d if a=2 b=4 c=10 d=15 express as a reduced fraction

I am Lyosha [343]

$\bf a^3b^{-2}c^{-1}d\implies \cfrac{a^3d}{b^2c}\qquad \begin{cases} a=2\\ b=4\\ c=10\\ d=15 \end{cases}\implies \cfrac{2^3\cdot 15}{4^2\cdot 10}\implies \cfrac{120}{160}\implies \cfrac{3}{4}$

6 0

4 years ago

Can someone help me understand and solve this? Plz...

valentinak56 [21]

320-70= 250
250X1/2=125
X=125

3 0

4 years ago

Read 2 more answers

Identify the segment bisector of AB¯¯¯¯¯¯¯¯. Then find AB.

tia_tia [17]

Answer:

is there more to the question? this does not make seince

Step-by-step explanation:

5 0

3 years ago

Assume c and d function independently. for the system to function, either c or d must function.

almond37 [142]

For the "system" to function, we require that $C\cup D$ occurs (i.e. the event that either $C$ or $D$ function properly). This occurs with probability

$\mathbb P(C\cup D)=\mathbb P(C)+\mathbb P(D)-\mathbb P(C\cap D)$

but since $C$ and $D$ are independent,

$\mathbb P(C\cup D)=\mathbb P(C)+\mathbb P(D)-\mathbb P(C)\mathbb P(D)$

We're given that $\mathbb P(C^C)=0.08$ and $\mathbb P(D^C)=0.12$ , so

$\mathbb P(C\cup D)=(1-0.08)+(1-0.12)-(1-0.08)(1-0.12)=0.9904$

If $\mathbb P(C^C)=\mathbb P(D^C)=p$ , then

$\mathbb P(C\cup D)=(1-p)+(1-p)-(1-p)^2=1-p^2$

4 0

4 years ago