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3 years ago

7

Can someone please help me with my questions please I really really need help.

1 answer:

iogann1982 [59]3 years ago

8 0

Answer:

not
28,45,53
37,36,45
10,24,26
not

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Can people help me please to find the volume about question number 10 please and tell me the answer step by step please I need h

Alecsey [184]

#10
Volume of a cylinder: $\pi$ r²h

Plug the numbers in.

$\pi$ 3²15 = <span>424
</span>
The volume of the pipe is 424 cm³.

7 0

4 years ago

Find the value of 3<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="abs

Alex

Answer:

The answer is

<h2>22</h2>

Step-by-step explanation:

3√x + 7

x = 25

Substitute the value of x into the expression

That's

3(√25) + 7

√25 = 5

So we have

3(5) + 7

= 15 + 7

<h3>= 22</h3>

Hope this helps you

8 0

4 years ago

Let T:P3â†’P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(

balu736 [363]

It looks like we're told that

$T(-2x^2)=3x^2+4x$

$T\left(\dfrac12x+3\right)=-3x^2+3x-4$

$T(2x^2-1)=-3x+4$

We use the fact that $T$ is linear to find $T(1),T(x),T(x^2)$ . First, we notice that

$T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)$

We also have

$T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)$

$T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)$

So once we find $T(1)$ , we can determine $T(x)$ and $T(x^2)$ . We have

$T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4$

and using this we find

$T(x)=12x^2+12x+16$

$T(x^2)=-\dfrac32x^2-2x$

Then

$T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)$

$T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c$

8 0

4 years ago

Unit rate for 15 degrees in 2 hours

Tpy6a [65]

A unit rate is something per one.

That means that we also need to include units so that we could know what we are talking about.

Basically divide, since this one is simple.

15/2 = 7.5

7.5 degrees per hour is our unit rate

4 0

3 years ago

Hurry please help I am struggling

Paraphin [41]

Volume = L x W x H

6.1 x 5.4 x 8 = 263.52 cm^3

5 0

3 years ago