All categories

2 years ago

Use the functions h(x) = 2x - 5 and t(x) = 6x + 4 to complete the function operations listed below.

Mathematics

1 answer:

Rom4ik [11]2 years ago

3 0

Answer:

See below for answers (in bold) and explanations

Step-by-step explanation:

Part A: (h+t)(x) = h(x) + t(x) = (2x-5) + (6x+4) = 2x - 5 + 6x + 4 = 8x - 1

Part B: (h*t)(x) = h(x) * t(x) = (2x-5) * (6x+4) = (2x)(6x) + (2x)(4) + (-5)(6x) + (-5)(4) = 12x² + 8x - 30x - 20 = 12x² - 22x - 20

Part C: h(t(x)) = h(6x + 4) = 2(6x + 4) - 5 = 12x + 8 - 5 = 12x + 3

You might be interested in

If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height, then find the ratio of the

Oduvanchick [21]

Given info:-If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.

Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?

Explanation:-

Let the radius of the right circular cylinder be r units

Let the radius of the right circular cylinder be h units

Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)

If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units

The height of the new right circular cylinder

= (1/4)×h units

⇛ h/4 units

Curved Surface Area of the new cylinder

= 2π(2r)(h/4) sq.units

⇛ 4πrh/4 sq.units

⇛ πrh sq.units --------(ii)

The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder

⇛ πrh : 2πrh

⇛ πrh / 2πrh

⇛ 1/2

⇛ 1:2

Therefore the ratio = 1:2

The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2

6 0

2 years ago

The volume of the prism is 81 m3.

Citrus2011 [14]

Answer:

27 m^3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

2.16 as a fraction in simplest form please explain if you can it would help a lot!

Ludmilka [50]

Answer:

54/25

Step-by-step explanation:

54/25 is the simplest form of 2.16 when writing as a fraction.

5 0

3 years ago

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone

ad-work [718]

Answer:

Part 1) The exponential function is equal to $y=1,350(0.95)^{x}$

Part 2) The population in 2010 was $992\ fish$

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

$a=1,350\ fish$

$b=(100\%-5\%)=95\%=0.95$

substitute

$y=1,350(0.95)^{x}$ ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

$y=1,350(0.95)^{x}$

For $x=(2010-2004)=6\ years$

substitute

$y=1,350(0.95)^{6}=992\ fish$

7 0

2 years ago

Help with this system of equations !! y = 3x + 21; y = -7x + 2

s2008m [1.1K]

C) x = -19/10 because when solving it with substitution u get x=-19/10 & y=153/10

3 0

3 years ago