Answer:
Step-by-step explanation:
The side opposite to greatest angle is longer
Angles in descending order, ∠B > ∠C > ∠A
Sides, CA > BA > BC
Answer:
A) Central angle has same measure as intercepted arc.
- mCE = mCD + mDE = 20° + 90° = 110°
B) Opposite angles of cyclic quadrilateral are supplementary.
- mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
- m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
- m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
- mQP = 360° - (90° + 76° + 72°) = 122°
C)
- m∠MLN = m∠MRN as same arc MN is intercepted
- m∠LMN is right angle as opposite side is diameter.
- ∠MNL is complementary with ∠MLN which is same as ∠MRN
- m∠MNL = 90° - 47° = 43°
D) Tangent secant angle is half of the intercepted arc.
<em>It seems wrong. Should be mQP instead of mQR</em>
- mQP = 2*m∠RQP = 2*74° = 148°
Might be wrong but y=2-2x
I = PRT
P = 300
R = 0.14
T = 2
now it is just a matter of subbing and doing the math
I = (300)(0.14)(2)
I = 84 <==
The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft