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RUDIKE [14]
3 years ago
5

A bag is filled with 4 red marbles, 3 blue marbles, 3 yellow marbles, and

Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0

Step-by-step explanation:

1) 4/12= answer --->1/3

2)2/12= -----> 1/6

3)3/12------>1/4

4) 1/9

its been so long since I did this so number 4 might be wrong

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-2w(w+8) what is the answer
Julli [10]
-2w (w + 8)
 Assuming that it is a polynomial from which you must find the roots, we must first rewrite it:
 -2w (w + 8) = 0
 The roots are then:
 w1 = 0
 w2 = -8
 Assuming you only have to rewrite the expression, the answer is:
 -2w ^ 2 -16w
 Answer:
 w1 = 0 
 w2 = -8
 -2w ^ 2 -16w
5 0
3 years ago
PLEASE HELP
katrin2010 [14]

The game that is  used for the scenario above in terms of fair play is  using a balloon. Here, the player will hit the balloon.

<h3>What is the scenario under the balloon game?</h3>

The rule of play are:

This is a classic game with simple rules which are:

  • Each player to hit the balloon up and it bonce into the air but when one should not allow it to touch the ground.,
  • Players would be tied together in twos and they will juggle a lot of balloon and it have to be more than 1 balloon with one of their hands tied to their back.

A scenario of the worksheet game whose expected value is 0 is given below:

Assume that it costs about $1 for a player to play the billon game and as such, if  the player hits a balloon, they will be given $3. what can you say. Can you say that it this game is fair or not? and who has the biggest advantage.

Solution

Note that a  game is ”fair” if the expected value is said to be 0. When a player is said to hits a balloon, their net profit often increase by $4.  So when the player do not hit a balloon, it drops to $1.

(4)(0.313) + (-1)(0.313)

= 0.939 approximately

Thus, the expected value is $0.939 which tells that the game is fair.

Learn more about fair play from

brainly.com/question/24855677

#SPJ1

4 0
2 years ago
Can you help me on these math problems?
densk [106]
I cannot help you unless I know what ones you need help on
8 0
3 years ago
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
Shalnov [3]

Answer:

We conclude that the true average percentage of organic matter in such soil is different from 3%.

Step-by-step explanation:

We are given that the values of the sample mean and sample standard deviation are 2.481 and 1.616, respectively.

Suppose we know the population distribution is normal, we have to test the hypothesis that does this data suggest that the true average percentage of organic matter in such soil is something other than 3%.

<em>Let </em>\mu<em> = true average percentage of organic matter in such soil</em>

SO, <u>Null Hypothesis</u>, H_0 : \mu = 3%   {means that the true average percentage of organic matter in such soil is equal to 3%}

<u>Alternate Hypothesis</u>, H_A : \mu \neq 3%   {means that the true average percentage of organic matter in such soil is different than 3%}

The test statistics that will be used here is <u>One-sample t test statistics</u> because we don't know about the population standard deviation;

                           T.S.  = \frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }  ~ t_n_-_1

where,  \bar X = sample mean amount of organic matter = 2.481%

              s = sample standard deviation = 1.616%

              n = sample of soil specimens = 30

So, <u><em>test statistics</em></u>  =  \frac{0.02481-0.03}{{\frac{0.01616}{\sqrt{30} } } }  ~ t_2_9

                               =  -1.759

<u></u>

<u>Now, P-value of the test statistics is given by;</u>

       P-value = P( t_2_9 > -1.759) = <u>0.046</u> or 4.6%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.046 which is clearly smaller than the level of significance of 0.05 (for two-tailed test), so we will reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the true average percentage of organic matter in such soil is different from 3%.

3 0
3 years ago
PLEASE HELP!! 25 POINTS This was already due and it's almost 1 AM-- I just need an explanation on one or all the answers if you
kirza4 [7]

Answer:

See below

Step-by-step explanation:

<em>Refer to attached</em>

34.

  • h(x) = 8 ⇒
  • x = 4 as per diagram

35.

  • g(8) = 4 as per table

36.

  • f(x) = 2 ⇒
  • x = -0.8 as per graph (approx.)

37.

  • f(2) = -2 as per graph

38.

  • h(-1) = -8 as per diagram

39.

  • g(x) = 4 ⇒
  • x = 9 or x = 8 as per table

6 0
2 years ago
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