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dolphi86 [110]
3 years ago
6

A line passes through the two glven points. Is it vertical, horizontal,or neither?

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

horizontal

Step-by-step explanation:

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Answer quickly please.
jeka57 [31]

Answer:

8.333333

Step-by-step explanation:

 3x+2(4+6x)=133

  3x+8+12x=133                      First I distibuted the 2 too the 4 and 6x

15x+8=133                                 Then I added the x es 3x and 12x

15x+8-8=133-8                         Then I subracted 8 from both sides

15x=125                                    That leaves with this

 15x/15=125/15                          Now I divide 15 from both sides to isolate x

x= 8.33333                                 that is the answer

                             check

                  3x+2(4+6x)=133

                 3*8.333333+2(4+6*8.333333)=133

                  24.999999 +2(4+ 49.999998)=133

                    24.999999+2( 53.999998)=133

                         24.999999+107.999996=133

                              132.999995=133

                       

                                 You can not get an exact answer for this problem

4 0
3 years ago
What is the value of s?​
Leya [2.2K]

Answer: a value is like how much is the pice or like counting money

Step-by-step explanation:

8 0
3 years ago
Graph the image of H(-8,5) after a reflection over the x-axis.<br><br> Answer ?
TEA [102]

Answer: plot a point at (-8, -5)

The y coordinate flips from positive to negative, or vice versa, when we reflect over the horizontal x axis. The x coordinate stays the same.

The rule can be written as (x,y) \to (x,-y)

6 0
3 years ago
Jameson was 5 years old y years ago. How old will he be in z years?
romanna [79]
5+y+z I think x Something like that.
8 0
3 years ago
140 subtracted from the square of a number the result is three times the number find the negative solution
natima [27]

Answer:

Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

5 0
3 years ago
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