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Juliette [100K]
2 years ago
13

Erasers cost 45 cents a piece. Notebooks cost 90 cents a piece . Karla spent $18 for a total of 28 erasers and notebooks . How m

any did she buy ?​
Mathematics
1 answer:
Tems11 [23]2 years ago
7 0

Answer:

12 Notebooks And 16 Erasers

Step-by-step explanation:

Let x represent the number of notebooks and y represent the number of erasers. (x+y=28) Then, input the cent numbers into the equation. (90x+45y=1800) The 1800 represents the amount of dollars spent. Then simplfy the equation, which gives you 12 notebooks and 16 erasers.

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How many apples are left in the tree if you started with 18 and ended with 11
ruslelena [56]

Answer:

Wouldn't it be 11? If the tree starts with 18 apples, and ends with 11, then that's it, it ends with 11 apples.

unless you just mis-typed, and meant 18-11. 7 would be the answer.

Step-by-step explanation:

7 0
3 years ago
If 2×2=4 and 4×4=8. What is 8×8?​
Oxana [17]

Answer:

64

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2 years ago
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X^2 +18 =15 could anyone help me with this?
stiv31 [10]

Answer:

x = i√3, -i√3

Step-by-step explanation:

Simply take the root of both sides, then solve.

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If a polynomial is divided by a binomial and there is a remainder what does that mean
Svetllana [295]
That means:

1) you cannot factorize it, or
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3 years ago
1. (Sec. 6.1) In a random sample of 80 components of a certain type, 12 are found to be defective. (a) Give a point estimate for
denis-greek [22]

Answer:

(a) 0.85

(b) 0.7225

Step-by-step explanation:

(a) The point estimate for the proportion of all such components that are not defective is given by the number of non-defective units in the sample divided by the sample size:

p=\frac{80-12}{80}\\p=0.85

The proportion is 0.85.

(b) Assuming that the sample is large enough to accurately provide a point estimate for the whole population, this can be treated as a binomial model with probability of success (non-defective part) p = 0.85. Since both components must be non-defective for the system to work, the probability of two successes in two trials is:

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An estimate of 0.7225 for the proportion of all such systems that will function properly.

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2 years ago
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