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Anettt [7]
3 years ago
13

X+5 divided by 3=15 what is the answer?

Mathematics
2 answers:
GREYUIT [131]3 years ago
4 0
All you have to do is solve for x. See the following steps below.

Step 1. Subtract \frac{5}{3} from both sides

X= 15-\frac{5}{3}

Step 2. Simplify 15- \frac{3}{5} to \frac{40}{3}

X= \frac{40}{3}
elena-14-01-66 [18.8K]3 years ago
3 0
( x + 5 ) / 3 = 15
x + 5 = 15 × 3
x + 5 = 45
x = 45 - 5
x = 40
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Answer:

88

Step-by-step explanation:

If there are 111 balls of 4 colors, if 100 are taken, and each at least 1 of each color appears, there has to be at least 12 of each color (if you take 100 marbles of 3 colors, all 11 of 1 color could still be in the box, so there has to be at least 12 of each). If there are 12 marbles of 3 colors, there would be 111-(12×3)=111-36-75 marbles of the last color. To get at least 1 marble in 3 colors add 75+12+1=88. If there are 12 marbles of 2 colors, there would be a combined total of 87 marbles for the other 2 colors. 87+1=88. If there is 12 marbles of 1 color, there would be a combined total of 99 marbles for the other 3 colors. If there was a divide of 97+1+1, the 2 colors with only 1 marble could have still been left in the box when 100 balls were taken. So there has to be at least 12 of the colors. So we get 111-12-12-12=75, which is the maximum number of marbles that 1 color can have. 75+12+1=88, our previous answer.

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7 0
3 years ago
A courier service advertises that its average delivery time is less than six hours for local deliveries. A random sample of size
Diano4ka-milaya [45]

Answer, Step-by-step explanation:

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3 0
3 years ago
What is -x/3 = 9. Solve for x
vlada-n [284]

Note: I just noticed that you only have one negative sign. If you mean to put -9, change the sign to positive. If not, leave the answer.

Note the equal sign. what you do to one side, you do to the other. Isolate the x. First, multiply 3 to both sides

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Next, to isolate the x, divide -1 from both sides

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3 0
4 years ago
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Answer:

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6 0
3 years ago
The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the
gladu [14]

Answer:

  • <u><em>The height of the missing rectangle is 0.15</em></u>

Explanation:

The image attached has the mentioned <em>histogram</em>.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

<u>1. Sum of the known relative frequencies</u>:

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<u>2. Missing frequency</u>:

  • 1 - 0.85 = 0.15

<u>3. Conclusion</u>:

  • The height of the missing rectangle is 0.15

4 0
3 years ago
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