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2 years ago

What is GCF and LCM of -5 and 56? Please Help! Will give Brainliest!

Mathematics

2 answers:

Otrada [13]2 years ago

6 0

Answer:

GCF= 1

LCM= 280

Step-by-step explanation:

GCF= Find the prime factorization of 5, 5 = 5

Find the prime factorization of 56, 56 = 2 × 2 × 2 × 7

Then multiply the prime factors both numbers have in common

LCM= multiply the two numbers together and ignore all negative signs

Nookie1986 [14]2 years ago

4 0

Answer:

The GCF is 1 and the LCM 280

Step-by-step explanation:

I did this on a test and got it right

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Simplify the expression. x2/3 · x7/2

WITCHER [35]

Answer:

x^2/3 x7/2

=1/6 x^9

Step-by-step explanation:

try using mathpapa

6 0

2 years ago

Julia is going to the store to buy candies. Small candies cost $4 and extra-large candies cost $12.She needs to purchase at leas

BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

2 years ago

Help plz:)))I’ll mark u Brainliest

Stolb23 [73]

Answer:

x=20

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

BRAINLIEST ANSWERS ONLY.

mars1129 [50]

Answer:

Heyy

Step-by-step explanation:

△ABC is a right angled triangle and right angle at B

sinA=

, cosA=

⟹sinA+cosA=

BC+AB

[We know that sum of two sides of a triangle is greater than the third side]

⟹sinA+cosA>

Hence, sinA+cosA>1

4 0

1 year ago

In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi

Nataliya [291]

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

3 0

2 years ago