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2 years ago

Find the value of x. Round to the nearest tenth. Please help!

Mathematics

2 answers:

Step2247 [10]2 years ago

4 0

The value of x is 11.3

Serhud [2]2 years ago

3 0

Answer:

17.138°

Step-by-step explanation:

180°=90°-35°-Unknown sum of angles in triangle

180°-125°=Unknown

unknown =55°

sin55/x=sin35/12

sin55°\x=0.047798036°

x=17.138°

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Volgvan

The arc angle AC is measured as 55 degrees.

<h3>How to find arc angle?</h3>

If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.

Therefore, the secants intersect outside the circle at point E.

The arc angle AC can be found as follows:

Therefore,

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

arc angle AC = x

arc angle BD = 23 degrees.

m∠BED = 16 degrees.

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

16 = 1 / 2 (x - 23)

16 = 1 / 2x - 23 / 2

16 + 11.5 = 0.5x

27.5 = 0.5x

x = 27.5 / 0.5

x = 55 degrees.

Therefore,

arc angle AC = 55 degrees.

learn more on arc angle here: hhttps://brainly.com/question/23117081

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7 0

1 year ago

Which of the following pieces are congruent?

posledela

Answer:

The horizontal segment of E and vertical segments of M.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Write an expression that represents the difference of 32 and N multiplied by 10

NISA [10]

(32-n)10________________

8 0

2 years ago

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4 1/3 - 2 1/2 please help Explanation:

galben [10]

Answer:

1 $\frac{5}{6}$

Step-by-step explanation:

First convert this mix number into a improper number

13/3-5/2

Then find the LCM of the denominator

26/6-15/6

Now simplify

11/6

1 $\frac{5}{6}$

Hope you got it

If you have any question just ask me

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8 0

3 years ago

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What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?

andrew11 [14]

we know that

the standard form of the equation of the circle is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

$x^{2} +y^{2} +8x-6y+21=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}+8x) +(y^{2}-6y)=-21$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9$

$(x^{2}+8x+16) +(y^{2}-6y+9)=4$

Rewrite as perfect squares

$(x+4)^{2} +(y-3)^{2}=4$

$(x+4)^{2} +(y-3)^{2}=2^{2}$

the center of the circle is $(-4,3)$

the radius of the circle is $2\ units$

therefore

the answer is

the radius of the circle is $2\ units$

8 0

2 years ago

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