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alina1380 [7]
3 years ago
9

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels

30 Quarters What is the probability that you reach into the jar and randomly grab a penny and then, without replacement, a dime
Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

P(Penny\ and\ Dime) = \frac{9}{116}

Step-by-step explanation:

Given

Pennies = 22

Dimes = 27

Nickels = 9

Quarters = 30

Required

P(Penny\ and\ Dime)

This is calculated as:

P(Penny\ and\ Dime) = P(Penny) * P(Dime)

Since it is a selection without replacement, the computation is:

P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}

So, we have:

P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}

P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}

P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}

P(Penny\ and\ Dime) = \frac{9}{116}

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