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3 years ago

Can someone answer these 3 questions? <3

Mathematics

2 answers:

bezimeni [28]3 years ago

6 0

Answer:

1. x=2

2. x=5

3.x=10

Step-by-step explanation:

Rudik [331]3 years ago

4 0

Answer:

1. x=2

2. x=5

3 x=10

Step-by-step explanation:

Hope this helps :)

You might be interested in

What is the value of y? <br><br><br> • 3 <br> • 4 <br> • 5<br> • 6

coldgirl [10]

I think the answer is 6 but I might not be right. Please don’t be mad if it’s wrong. :(

5 0

3 years ago

Read 2 more answers

Please help me I need to turn in tomorrow please help me

Monica [59]

Answer:

<em>Answer: A. 0.2</em>

Step-by-step explanation:

<u>Probability</u>

The circle graph shows the distribution of the makeup of the Riverside Municipal Choir.

The total number of choir sections is: 8+10+10+12=40

To calculate the probability of a member chosen at random comes from the alto section, we use the formula:

$\displaystyle P=\frac{8}{40}$

Calculating:

P = 0.2

Answer: A. 0.2

7 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago

Isolate the x <br>3x+3y=-3

kirza4 [7]

Answer:

Step-by-step explanation:

3x + 3y = -3 given

3x = -3y - 3 subtract 3y from both sides

x = -y -1 divide everything by 3

hope this helps <3

3 0

3 years ago

dangina [55]

Answer:

$3w+10>2w+15$

Step-by-step explanation:

If Jerry initially releases 10 videos a week and creates an additional 3 each week, he will create a total of $3w+10$ videos, where $w$ is the number of weeks. If Martin initially releases 15 videos a week and creates an additional 2 each week, he will create a total of $2w+10$ videos, since $w$ is maintained. Therefore, the inequality $\fbox{$3w+10>2w+15$}$ can be used to find who creates more videos, where $w$ is the number of weeks.

7 0

2 years ago