Question

GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What

Answer 1

Answer:

hey there hope this answer helps you out

Step-by-step explanation:

we have two functions f(x) and g(x) such that

$f(x) = \frac{1}{x}$

and

$g(x) = {x}^{2} + 6x$

solving for f ° g, we'll substitute the x in f(x) by the value of g(x)

$fog = \frac{1}{g(x)}$

$fog \: = \frac{1}{ {x}^{2} + 6x }$

taking x common in denominator

$fog = \frac{1}{x(x + 6)}$

for a function to exist it should not have 0 in its denominator

checking the values of x for which the denominator of f ° g becomes 0 :-

• x = 0 and
• x = -6

so the function doesn't exist at values x = 0, -6

So, 0, -6 cannot be in the domain of f°g