EXAMPLE
Find the distance between the points A(−4, −3) and B(5, 7).
SOLUTION
In this case, x1 = −4, x2 = 5, y1 = −3 and y2 = 7.
AB2 = (x2 − x1)2 + (y2 − y1)2
= (5 − (−4))2 + (7 − (−3))2
= 92 + 102
= 181
Thus, AB =
Note that we could have chosen x1 = 5, x2 = −4, y1 = 7 and y2 = −3 and still obtained the same result. As long as (x1, y1) refers to one point and (x2, y2) the other point, it does not matter which one is which.
Answer: d) 95 degrees
Step-by-step explanation:
To find this solution, simply subtract -20 from 75, to get 95. In reality, you would take the absolute value of one temperature - another, but all you need to remember is to always subtract the smaller temperature from the larger.
The slope is 0.5, hope this helps
1 hamper box, curated by Jithu can be contained 5 cupcakes.
<h3>Calculation:</h3>
The total amount of cupcakes =665 nos.
Jithu wants to create a gift box, each of which contains 6 cupcakes.
We have to see first, whether 665 could be equally distributed or not.
Hence, 665/6= 110.84 unit
It is seen that the number is in a fraction.so, It can be said that 665 cakes cannot be equally distributed to each gift pack carrying 6 cakes.
Hence, 110*6=660 cupcakes.
∴665-660= 5 cupcakes in one box
So, it is concluded that Jithu could be prepared 110 gift boxes containing 6 cakes each & 1 box containing 5 cupcakes.
Learn more about cake-related problems:
brainly.com/question/25225029?referrer=searchResults
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