Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
yes # 7
Step-by-step explanation:
729 times 59049
59778 is the answer
Step-by-step explanation:
When a number is grouped with the x in this problem it will move the graph right (if it is is minus) and it will
move it left ( if it is plus), therefore the original graph will be move to the left 5 units.
<em>Length = </em><em>80</em>
<em>Breadth = </em><em>30</em><em> </em>
<em>Height = </em><em>30</em>
<em>Total surface area of a cuboid is= </em>
<em><u>2 ( lb + bh + hl )</u></em>
<em>Putting the values in the formula,</em>
<em>We get,</em>
<em>= 2</em><em> [</em><em> (80 x 30) + (30 x 30) + (30 x 80)</em><em>]</em>
<em>= 2 (2400 + 900 + 2400)</em>
<em>= </em><em><u>8100 cm²</u></em>
<em></em>
<em>THANK YOU!!</em>
<em>∝ </em><em>Sidhdi</em>