(6,-3)(-4,-9)
slope(m) = (-9 -(- 3) / (-4 - 6) = (-9 + 3) / -10 = -6/-10 = 3/5
y - y1 = m(x - x1)
slope(m) = 3/5
(6,-3)....x1 = 6 and y1 = -3
now we sub
y - (-3) = 3/5(x - 6) =
y + 3 = 3/5(x - 6) <==
Step-by-step explanation:
6/9 divide top and bottom by 3 to get 2/3
Now reduce each of the fractions to the lowest terms, and look for one that gives 2/3.
12/8 = 3/2 (divide by 4 top and bottom)
8/12 = 2/3 (divide by 4 top and bottom) This is a solution
10/12 = 5/6 (divide by 2 top and bottom)
8/13 (cannot be reduced)
Therefore the second fraction (8/12) forms a proportion with 6/9.
Answer:
i dont know im just doing this for the points
Answer:
Step-by-step explanation:
Given that:
To bet $5 that the outcome is any one of these five possibilities: 0, 00, 1, 2, 3.
Let Y represent the Amount of net profit
Then, Y= {-5, 30}
The probability distribution of Y is:
Y -5 30
P(Y=y)

a) The expected value of X is given by:
![E[Y] =\sum y P(Y=y)= 30*\dfrac{5}{38}-5*\dfrac{33}{38}](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%5Csum%20y%20P%28Y%3Dy%29%3D%2030%2A%5Cdfrac%7B5%7D%7B38%7D-5%2A%5Cdfrac%7B33%7D%7B38%7D)


b)
On a bet of $5 on the number 25 we are expected to loose 24 cents.
While on a $5 bet that the outcome is any one of the numbers 0,00, or 1 we are expected to loose 39 cents.
Hence, $5 bet on the number 27 is better. Because the expected loss is less in this bet