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3 years ago

Plz help

Mathematics

1 answer:

ella [17]3 years ago

4 0

Answer:

Step-by-step explanation:

If the probability of choosing a strike is 3/10, that means that from the total items available 3 out of 10 are strikes, now, if there are 9 strikes total, this is the equation representing such result:

(3/10)(totalChips) = 9

if we solve for totalChips we have:

3(totalChips) = 9*10 = 90

totalChips = 90/3 = 30

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One minute after it is released, a hot-air balloon rises 120 feet. In each succeeding minute, the balloon rises only 60% as far

MArishka [77]

Answer:

25.92 feet

Step-by-step explanation:

In the first minute, the hot air balloon rises 120 feet.

And it is given that, the balloon rises in a minute only 60% of the height it rose in the previous minute.

Therefore, in the second minute, the balloon rises by (120×0.6) =72 feet

And in the third minute, the balloon rises by (72×0.6) =43.2 feet

Hence, in the fourth minute, the balloon rises by (43.2 ×0.6) =25.92 feet (Answer)

7 0

3 years ago

Read 2 more answers

a pentagon is a regular pentagon that has 5 sides, so each side has the same length that is (x - 1.5)cm. The perimeter is 22.5 c

Ivanshal [37]

Answer:

Step-by-step explanation:

5(x - 1.5) = 22.5

5x - 7.5 = 22.5

5x = 15

x = 3

8 0

3 years ago

Math

Snezhnost [94]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

$\qquad \sf \dashrightarrow \: 7.2 + (2x + 0.4)$

$\qquad \sf \dashrightarrow \: 7.2 + 2x + 0.4$

$\qquad \sf \dashrightarrow \: 7.2 +0.4 + 2x$

$\qquad \sf \dashrightarrow \: (7.2 +0.4) + 2x$

Therefore, the correct choice is A

3 0

2 years ago

Read 2 more answers

Derivative of tan(2x+3) using first principle

kodGreya [7K]

$f(x)=\tan(2x+3)$

The derivative is given by the limit

$f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h$

You have

$\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h$

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

$\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}$

By this identity, you have

$\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}$

So in the limit you get

$\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}$
$\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}$

The first two limits are both 1, and the single term in the last limit approaches 0 as $h\to0$ , so you're left with

$f'(x)=\dfrac12\sec^2(2x+3)$

which agrees with the result you get from applying the chain rule.

7 0

3 years ago

Pls help with this question

Talja [164]

Answer:

point A is x=4 and y=12

point B is x=16 and y=32

6 0

2 years ago