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olchik [2.2K]
3 years ago
8

HELP ME OUT PLEASEUse the data to create a scatter plot. ​

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0
在校生總數是因為我們都用都要看什麼看的很有些是般生台的中國民
musickatia [10]3 years ago
5 0
Every unit on the left side of the table is going to go on the horizontal or x axis. With a measurement of 2 you got 2 to the right of the origin. Then the right side of the table is the vertical or y axis. And your first number there is one so after you go two right of the origin go up one. Now do that for all pairs, do not connect any lines and remember the rule for graphs, first you go in the elevator (act on x first) then you go up (y next)
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No files!!! <br> Will give brainliest and please don’t guess
ohaa [14]

Answer:

i think its 54. i might be incorrect.

Step-by-step explanation:

7 0
3 years ago
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The cone below has a radius of 3 inches, a height of 4 inches, and a slant height of 5 inches. What is the approximate lateral a
Bond [772]

Answer:47

Step-by-step explanation:

4 0
3 years ago
What is the volume of the prism 8 ft 3 ft 2 ft ( i ready) <br> (Cubic feet)
Oksanka [162]

Answer:

48ft^2

Step-by-step explanation:

volume= length x width x height

8 x 3 x 2 = 48

3 0
2 years ago
Help with this question
Mariulka [41]

Answer:

I think its 68(pi)

Step-by-step explanation:

u must get first the slant height then get the SA of the cone and get the SA of the cylinder and add them but don't forget to subtract a base from ur final answer

7 0
3 years ago
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Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.​
zlopas [31]

Answer:

x = 1

Explanation:

\sf \rightarrow log(3x) + log(x + 4) = log(15)

Rule: log(a) + log(b) = log(ab)

\sf \rightarrow log(3x(x + 4)) =  log(15)

cancel out log on both sides

\sf \rightarrow 3x(x + 4) = 15

relocate constant variable

\sf \rightarrow 3x^2 + 12x -15 = 0

take 3 as a common factor

\sf \rightarrow 3(x^2 + 4x -5) = 0

divide both sides by 3

\sf \rightarrow x^2 + 4x -5 = 0

middle term split

\sf \rightarrow x^2 + 5x -x-5 = 0

factor common terms

\sf \rightarrow x(x  + 5) -1(x+5)= 0

collect into groups

\sf \rightarrow (x-1)(x+5)= 0

set to zero

\sf \rightarrow x-1 = 0 , \ x+5= 0

relocate variables

\sf \rightarrow x = 1,  \ x = -5

There must be a positive solution for log, so the solution is only x = 1

3 0
2 years ago
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