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2 years ago

A) all values at which h has a local maximum B ) all local maximum values of h

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

4 0

For the given function h(x), we have:

a) at x = -2 and x = 2.

b) y = 0 and y = 3.

<h3>How to identify the maximums of function h(x)?</h3>

First, we want to get the values of x at which we have maximums. To do that, we need to see the value in the horizontal axis at where we have maximums.

By looking at the horizontal axis, we can see that the maximums are at:

x = -2 and at x = 2.

Now we want to get the maximum values, to do that, we need to look at the values in the vertical axis.

The first maximum value is at y = 0 (the one for x = -2)
The second maximum is at y = 3 (the one for x = 2).

If you want to learn more about maximums:

brainly.com/question/1938915

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I need to model 2 equivalent fractions for 6 fifths

masha68 [24]

Six fifths = $\frac{6}{5}$ .
You can multiply the numerator and denominator by any number to find an equivalent fraction.
Two examples of equivalent fractions would be $\frac{12}{10}$ and $\frac{18}{15}$ .
Hope that helped you.

3 0

4 years ago

Complete the equivalent equation for -7x-60 =x^2 +10x

alex41 [277]

Answer:

(x+12)(x+5)

Step-by-step explanation:

Formula use: a²+bx+c

Make one side equal to zero:

Original:

-7x-60 =x² +10x

New:

x² + 17x + 60

Multiply A with C

New:

(1)x x 60 = 60

Find factors of 60 that when added, equal to 17.

New:

10 × 6, 60 × 1, 20 × 3, <u>5 × 12</u>, 4 × 15

5 times 12 equal 60, but when added equal to 17.

Replace the 17 with 5 and 12

New:

x² + 5x + 12x + 60

Break them off into two equations

New:

x² + 5x l 12x + 60

Divide each equation into it's simpilest form. Make sure the numbers in the ( ) are the same.

New:

x(x + 5) l +12(x+5)

Answer: (x+12)(x+5)

6 0

3 years ago

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

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3 years ago

An athlete eats

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It is 60,000 milligrams

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3 years ago

What is the solution set for x2+25=0

Masja [62]

Step-by-step explanation:

${x}^{2} + 25 = 0 \\ \therefore {x}^{2} = - 25 \\ \therefore {x} = \sqrt{ - 25} \\ \therefore {x} = \pm\sqrt{ - 1 \times 25} \\ \therefore {x} = \pm \sqrt{ 25} \times \sqrt{ - 1} \\ \therefore {x} = \pm5 \: i \\ \therefore {x} = \{ - 5i, \: \: 5i \} \: \\ is \: the \: solution \: set.$

7 0

3 years ago