So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0
x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer
x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7
smalles is 5
Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
flog6e
Step-by-step explanation:
I got it right on edg
Answer:
x = -4 and x = -14
Step-by-step explanation:
Our equation is (x + 9)² = 25
Applying the square root property we would need to take the square root of both sides: 
This give us x + 9 = ±5
Here we have two equations since taking the square root gives us a positive and negative value
Our first equation is x + 9 = 5, and to isolate the variable we would need to subtract 9 from both sides, giving us x = -4
Our second equation is x + 9 = -5, and to isolate the variable we would need to subtract 9 from both sides, giving us x = -14
