Answer:
4b + 10c= T
Step-by-step explanation:
Answer:
- A. segment A double prime B double prime = segment AB over 2
Step-by-step explanation:
<u>Triangle ABC with coordinates of:</u>
- A = (-3, 3), B = (1, -3), C = (-3, -3)
<u>Translation (x + 2, y + 0), coordinates will be:</u>
- A' = (-1, 3), B = ( 3, -3), C = (-1, -3)
<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>
- A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)
<u>Let's find the length of AB and A''B'' using distance formula</u>
- d = √(x2-x1)² + (y2 - y1)²
- AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
- A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13
<u>We see that </u>
<u>Now the answer options:</u>
A. segment A double prime B double prime = segment AB over 2
B. segment AB = segment A double prime B double prime over 2
- Incorrect. Should be AB = A''B''*2
C. segment AB over segment A double prime B double prime = one half
- Incorrect. Should be AB/A''B'' = 2
D. segment A double prime B double prime over segment AB = 2
- Incorrect. Should be A''B''/AB = 1/2
Answer:
-4x
Step-by-step explanation:
5x - 9x
Factor out x
x( 5-9)
x ( -4)
-4x
Answer:
Yes
Step-by-step explanation:
Answer:
Option (2)
Step-by-step explanation:
Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.
From the figure attached,
m∠C = ![\frac{1}{2}[m(\text{major arc AB})-m(\text{minor arc AB)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%20AB%7D%29-m%28%5Ctext%7Bminor%20arc%20AB%29%7D%5D)
= ![\frac{1}{2}[(360-m\widehat{AB})-m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28360-m%5Cwidehat%7BAB%7D%29-m%28%5Cwidehat%7BAB%7D%29%5D)
= ![\frac{1}{2}[360-2m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B360-2m%28%5Cwidehat%7BAB%7D%29%5D)
= 
= 180 - 150
= 30°
Therefore, measure of angle C will be 30°.
Option (2) is the answer.
