All categories

3 years ago

Find the perimeter and area of the figure to the nearest hundredth use 3.14 for pi.

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer:

Perimeter = 36.84 ft

Area = = 64.26 ft²

Step-by-step explanation:

✔️Perimeter of the figure = the length of the surrounding border the rectangle + surrounding border of circle

Length for surrounding border of the rectangle = 3 + 3 + 3 + 3 + 3 + 3 = 18 ft

Surrounding border of a circle = circumference of a full circle (two half circle makes 1 full circle)

Circumference of the circle = πd

diameter (d) = 12 - (3 + 3) = 6 ft

π = 3.14

Circumference = 3.14*6

= 18.84 ft

✅Perimeter = 18 + 18.84 = 36.84 ft

✔️Area = area if the rectangle + area of the full circle

= L*W + πr²

L = 12 ft

W = 3 ft

π = 3.14

r = ½(6) = 3 ft

Plug in the values

Area = 12*3 + 3.14*3²

= 36 + 28.26

= 64.26 ft²

You might be interested in

Determine if the differential equation is linear or non-linear. y''+2yy'+3y=0

Otrada [13]

Nonlinear because y is squared

7 0

3 years ago

I don't know how to get the answer for number 5

marysya [2.9K]

280
M=40x1
200 divided by 5 equals 40 so 40 times 7 equals 280

6 0

3 years ago

Use the equation 135 x 42 = 5.670 and what you know about fractions, decimals, and place value to explain how to place the decim

ozzi

Answer:

5.670

Step-by-step explanation:

To compute 1.35 x 4.2

First, we need to convert both decimals to fraction

1.35 = 135/100

4.2 = 42/10

Taking the product

1.35 x 4.2

= 135/100 * 42/10

= (135*42)/(100*10)

= 5670/1000

= 5.670

Hence the product of both numbers is 5.670

8 0

3 years ago

PLEASE HELP !!!!!

Anastaziya [24]

Answer:

-10%

Step-by-step explanation:

price elasticity of demand = % change in demand / % change in price

Here, the "price" changes from 15 to 45, so its percent change is ...

((new value)/(old value) -1) × 100%

= (45/15 -1) × 100%

= 200%

The % change in demand is given as -20%, so the price elasticity is ...

price elasticity of demand = (-20%)/(200%) = -0.10 = -10%

8 0

3 years ago

Hey does any body know how i can approximate 13 like this had this homework but it got late on me.

Illusion [34]

Answer:

(see attachment)

To approximate the square root of 13:

Working from the top down...

Enter the number you are trying to approximate in the top box: $\boxed{\sf \sqrt{13}}$

Find the perfect squares directly below and above 13.

Perfect squares: 1, 4, 9, 16, 25, 36, ...

Therefore, the perfect squares below and above 13 are: 9 and 16

Enter these with square root signs in the next two boxes: $\boxed{\sf \sqrt{9}}$ and $\boxed{\sf \sqrt{16}}$

Carry out the operation and enter $\boxed{\sf 3}$ and $\boxed{\sf 4}$ in the next two boxes.

Enter the number you are trying to square root (13) in the top left box, the perfect square above it (16) in the box below, then the perfect square below it (9) in the two boxes to the right of these. Carry out the subtractions and place the numbers in the boxes to the right.

$\dfrac{\boxed{\sf 13}-\boxed{\sf 9}}{\boxed{\sf 16}-\boxed{\sf 9}}=\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}$

Now enter the number you are trying to square root (13) under the square root sign. Place the square root of the perfect square below it (3) in the box to the right. Copy the fraction from above (4/7). Finally, enter this mixed number into a calculator and round to the nearest hundredth.

$\sf \sqrt{13}=\boxed{\sf3}\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}=\boxed{\sf3.57}$

7 0

2 years ago