Answer:
12.4 cm³
Step-by-step explanation:
From the picture attached,
Radius of the circular top of the cone =
= 
Height of the cone = h
Lateral height of the cone = h
By applying Pythagoras theorem in the right triangle of the cone,
l² = r² + h²
6² = 1² + h²
h = 
h = 
Ice cream needed to fill one cone = Volume of the cone
Since, formula for the volume of the cone V = 
V = 
= 6.195
≈ 6.20 cm³
Ice cream needed to fill the two cones = 2 × 6.20
= 12.4 cm³
Therefore, ice cream needed to fill the two cone = 12.4 cm³
Step-by-step explanation:
2a - 7 - 6a = 9
- 4a - 7 = 9
- 4a = 16
a = -4
Answer:
The initial value of the function is <u>2</u>
The base of the function is <u>3</u>
The function shows exponential <u>growth</u>
Step-by-step explanation:
f(x) = 2(3^x)
Exponential functions are those with the following equation:
y = a*b^x
where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.
<em>a</em> is the y-intercept and <em>b </em>is the base.
The initial value of the function is the same as the y-intercept
If <em>a</em> is positive, the function growth. If <em>a</em> is negative, the function decay
The Greatest Common Factor of the given expression should be that expression that can divide both. First, factor both expression,
x^4 = (x³)(x) and x³ = (x³)(1)
Therefore, both can be factored by x³. The answer is the third choice.
Answer:
The question is incomplete, but the step-by-step procedures are given to solve the question.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.575.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M.
The upper end of the interval is the sample mean added to M.
The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).