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2 years ago

Helppppppppppppppppppppp

Mathematics

2 answers:

Step2247 [10]2 years ago

7 0

the answer is b 20%

SashulF [63]2 years ago

5 0

Answer:

B 20%

Step-by-step explanation:

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800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

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Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

Let the liters of 90% saline solution mix be $x.$

And let the liters of 40% saline solution mix be $y.$

So, the total number of liters:

$x+y=2000.$

$y=2000-x\ \ \ ....(1)$

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$90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000$

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Substituting the value of $y$ from equation (1) we get:

$0.9x+0.4(2000-x)=1200$

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Subtracting both sides by 800 we get:

$0.5x=400$

Dividing both sides by 0.5 we get:

$x=800.$

The liters of 90% saline solution mix = 800.

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$y=2000-x$

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