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Snowcat [4.5K]
2 years ago
14

Which of the following sets of ordered pairs defines a relation that

Mathematics
1 answer:
yawa3891 [41]2 years ago
8 0

para lang po sa points hehe

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Becky leaves home and rides a distance of 30 km. It took her 2.5 hours. What is her speed¿
kramer
Distance=speed times time
distance/time=speed

distance=30km
time=2.5hr

distance/time=30km/2.5hr=60km/5hr=12km/1hr=12km/hr

her speed is 12km per hour
3 0
3 years ago
Read 2 more answers
-4 5/1 - 6 4/6=??? help!
yanalaym [24]

Answer:

-15 2/3.

Step-by-step explanation: First off, I performed the equation -4 5/1 - 6 4/6, yielding -15.6. I then translated that to a fraction. How to do that, you ask?

Example #1

Convert 0.32 to fraction:

0.32 = 32/100

Find the greatest common divisor (gcd) of the numerator and the denominator:

gcd(32,100) = 4

Reduce the fraction by dividing the numerator and the denominator with the gcd:

0.32 = (32/4) / (100/4) = 8/25

Example #2

Convert 2.56 to fraction:

2.56 = 2+56/100

Find the greatest common divisor (gcd) of the numerator and the denominator:

gcd(56,100) = 4

Reduce the fraction by dividing the numerator and the denominator with the gcd:

2+56/100 = 2 + (56/4) / (100/4) = 2+14/25  

In your problem the final answer would result in -15 2/3. Hope this answered your question.

6 0
3 years ago
Read 2 more answers
HelPpPppP plEasEeEEeeEeEeEeEeEEEeE
Vika [28.1K]
1. This answer would be C, n^3 + 5
2. This answer would be D, n^3 + 9
3. This answer would be A, 4n - 11
5 0
3 years ago
The thickness of a block is approximately 2 centimeters. How many blocks are in a stack that is 1,000 millimeters high? ( 1 cm =
dangina [55]

Answer:

1block=2cm

1cm=10mm

therefore 1block=2×10=20

1000÷20=50

=50blocks

5 0
3 years ago
Read 2 more answers
Sydney wrote the equation y+1=12(x−3). y + 1 = 1 2 ( x − 3 ) . Explain her error and then write the correct equation in point-sl
yanalaym [24]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given equation:

\to y + 1 = 12 ( x - 3 )

Using formula:

\to \bold{y = mx +c}

Solving the given equation:

\to y + 1 = 12 ( x - 3 )\\\\\to y+1 =12x-36\\\\\to y=12x-36-1\\\\\to y= 12x-37\\\\

compare the value form the given formula:

\to m= 12

Correct equation \to  y= 12x-37

solpe \to m= 12

4 0
3 years ago
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