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Makovka662 [10]
2 years ago
9

Please Show Your Work!

Mathematics
1 answer:
timurjin [86]2 years ago
8 0

Answer:

You have to have a Y and X axis line it may help. You can also time the few and yeah your smart you can do this i can help with more.

Step-by-step explanation:

I do this work. Thanks have a splendid life! Ask 4 me to solve more! Byes!

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Whats the answer to #1
maw [93]

Answer:

-8/5 or 1.6

Step-by-step explanation:

if you get the 2 points on the graph and use slope formula you get the answer

4 0
2 years ago
Which ordered pair is a solution of the equation 7x−5=4y−6?
Kaylis [27]
D. Neither A nor B. There you go.
5 0
3 years ago
Read 2 more answers
For the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7? 3 28
Oliga [24]

Answer:

The value of x is \frac{7}{4}.

Step-by-step explanation:

It is given that the inverse variation equation is

xy=k                  ..... (1)

The value of y is 4 and the value of k is 7.

Substitute y=4 and k=7 in equation (1).

x\times 4=7

Divide both sides by 4.

\frac{x\times 4}{4}=\frac{7}{4}

x=\frac{7}{4}

Therefore the value of x is \frac{7}{4}.

7 0
3 years ago
Read 2 more answers
Helppppp plsssss!!!<br><br>Thanks!!
Anvisha [2.4K]

Answer:

D

Step-by-step explanation:

using the rule of exponents

• (a/b)^{n} = a^{n} / b^{n}, hence

(7/4)^{11} = 7^{11} / 4^{11} → D



8 0
3 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
3 years ago
Read 2 more answers
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