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2 years ago

Write a division problem. Show two different ways that you can estimate the quotient using compatible numbers.

1 answer:

3 0

98 divided by 7

1. 98-round to 100
7-round to 10

100 divided by 10=10

So 98 divided by 7 is about 10

That is one way

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Using the protractor, find the angle measure.

Andrej [43]

Answer:

140°

Step-by-step explanation:

155°-15° =140°

4 0

3 years ago

The seats at a local baseball stadium are arranged so that each row has 5 more seat than the row in front of it. If there are fo

ohaa [14]

You would do an arithmetic sequence
use A1 +(n-1)d to calculate number of seats in the last row

An = 4+(24-1)5
An = 4 + (23)(5)
An = 4 + 115
An = 119 seats in the last row

now use a sum sequence to find total number of seats

Sn = n(a1 + an)/2
Sn = 24(4+119)/2
Sn = 24(123) /2
Sn = 1476 total seats

4 0

2 years ago

Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)). 5 7 9 10

AlladinOne [14]

The correct answer is 10.

In order to evaluate any composite function, you need to first put the value in for the inside function. In this case f(x) is on the inside along with the number 3. So, we input 3 in for x in f(x).

f(x) = 2x + 1

f(3) = 2(3) + 1

f(3) = 6 + 1

f(3) = 7

Now that we have the value of f(3), we can stick the answer in for the outside function, which is g(x).

g(x) = (3x - 1)/2

g(7) = (3(7) - 1)/ 2

g(7) = (21 - 1)/2

g(7) = 20/2

g(f(3)) = 10

5 0

3 years ago

Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int

Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula : $A=P(1+r)^t$

$A=5000(1+0.04)^3$

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{2})^{2 \times 3}$

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{4})^{4 \times 3}$

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{12})^{12 \times 3}$

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0

3 years ago

Write and simplify an expression for the perimeter of each figure.

xxTIMURxx [149]

3a- 2b + 8b - 2 + 6a + 3c
3a + 6a -2b +8b + 3c - 2
9a + 6b + 3c - 2

4 0

3 years ago