All categories

2 years ago

I need help with only one question on number 4? anyone pls?

Mathematics

1 answer:

Murljashka [212]2 years ago

4 0

I think 2,-2 is right

You might be interested in

Please Solve this Lines and angles question

Kay [80]

Answer:

133°

Step-by-step explanation:

As vertically opposite angles are equal,

< B E D = < F E G

Therefore,

< B E D = 47°

We know that co - interior angles which occur between 2 parallel lines, are added up to 180°.

Given that, < A B E = x

Therefore,

< B E D + < A B E = 180 °

47 + x = 180

x = 180 - 47

x = 133°

Let me know if you have any other questions. :)

8 0

2 years ago

My picture is my question

zvonat [6]

Answer:

Step-by-step explanation:

7 0

2 years ago

Simplify 8(x + 3) - 2x. Answer options: A) 6 x + 3 B) 7 x C) 6 x + 24

s344n2d4d5 [400]

Answer:

Expand the bracets then simplfy and then factorise

4 0

2 years ago

Read 2 more answers

Use the image below to answer the following question.

Rainbow [258]

Answer:9

Step-by-step explanation:pp

3 0

3 years ago

What is the simplified expression for,

Nostrana [21]

Here are a few rules you need to know for this equation:

Multiplying exponents of the same base: $x^m\times x^n=x^{m+n}$
Dividing exponents of the same base: $\frac{x^m}{x^n}=x^{m-n}$
Turning a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m$

So this is our algebraic expression: $\frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}$

Firstly, multiply 3^-4 and 3^2: $\frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}$

Next, divide:

$\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}$

Next, turn the negative exponent into a positive one: $3^12^{-1}= \frac{3}{2}$

Your final answer is 3/2, or 1.5.

6 0

3 years ago